Reading time

How long does it take to read War of Honor?

War of Honor by David Weber is about 883 pages, so it takes about 15½ hours at an average 238 words per minute — about 31 days at 30 minutes a day.

At an average reading speed

15 h 28 min

War of Honor · David Weber · first published 2002

Pages
883
30 min a day
31 days

By reading speed

Unhurried reader · 180 wpm20 h 26 min
Average adult · 238 wpm15 h 28 min
Quick reader · 300 wpm12 h 16 min
Very fast reader · 400 wpm9 h 12 min

By daily habit

Your reading speed

15 minutes a day62 days
30 minutes a day31 days
45 minutes a day21 days
60 minutes a day16 days

Page count: median of 9 editions on Open Library. Times assume about 250 words per page. How we calculate.

#10 in Honor Harrington

Next in the series: At All Costs (2005, 868 pages)

Your real reading speed

Time your sessions and Bookwisp learns how fast you actually read.

Start the timer when you open the book; it keeps running on your Lock Screen. Stop it, note your page, and your weekly minutes and streak update.

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The Now screen in Bookwisp with the books in progress

War of Honor: reading time questions

How many pages is War of Honor?
War of Honor is about 883 pages. That is the median across the 9 editions listed on Open Library; hardcover, paperback and large-print editions differ.
How long does it take to read War of Honor?
About 15 h 28 min at 238 words per minute, the average silent reading speed for adults. A quick reader at 300 words per minute needs about 12 h 16 min.
How many days to read War of Honor at 30 minutes a day?
About 31 days. At 15 minutes a day it takes about 62 days, and at an hour a day about 16 days.
What number is War of Honor in the Honor Harrington series?
War of Honor is book 10 in Honor Harrington by David Weber.

Books of about the same length