Reading time

How long does it take to read The Big Four?

The Big Four by Agatha Christie is about 223 pages, so it takes about 4 hours at an average 238 words per minute — about 8 days at 30 minutes a day.

At an average reading speed

3 h 54 min

The Big Four · Agatha Christie · first published 1927

Pages
223
30 min a day
8 days

By reading speed

Unhurried reader · 180 wpm5 h 10 min
Average adult · 238 wpm3 h 54 min
Quick reader · 300 wpm3 h 6 min
Very fast reader · 400 wpm2 h 19 min

By daily habit

Your reading speed

15 minutes a day16 days
30 minutes a day8 days
45 minutes a day6 days
60 minutes a day4 days

Page count: median of 121 editions on Open Library. Times assume about 250 words per page. How we calculate.

#4 in Hercule Poirot

Next in the series: The Mystery of the Blue Train (1928, 257 pages)

Your real reading speed

Time your sessions and Bookwisp learns how fast you actually read.

Start the timer when you open the book; it keeps running on your Lock Screen. Stop it, note your page, and your weekly minutes and streak update.

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The Now screen in Bookwisp with the books in progress

The Big Four: reading time questions

How many pages is The Big Four?
The Big Four is about 223 pages. That is the median across the 121 editions listed on Open Library; hardcover, paperback and large-print editions differ.
How long does it take to read The Big Four?
About 3 h 54 min at 238 words per minute, the average silent reading speed for adults. A quick reader at 300 words per minute needs about 3 h 6 min.
How many days to read The Big Four at 30 minutes a day?
About 8 days. At 15 minutes a day it takes about 16 days, and at an hour a day about 4 days.
What number is The Big Four in the Hercule Poirot series?
The Big Four is book 4 in Hercule Poirot by Agatha Christie.

Books of about the same length