Reading time
How long does it take to read Hallowe'en Party?
Hallowe'en Party by Agatha Christie is about 244 pages, so it takes about 4½ hours at an average 238 words per minute — about 9 days at 30 minutes a day.
At an average reading speed
4 h 16 min
Hallowe'en Party · Agatha Christie · first published 1969
- Pages
- 244
- 30 min a day
- 9 days
By reading speed
| Unhurried reader · 180 wpm | 5 h 39 min |
| Average adult · 238 wpm | 4 h 16 min |
| Quick reader · 300 wpm | 3 h 23 min |
| Very fast reader · 400 wpm | 2 h 33 min |
By daily habit
Your reading speed
| 15 minutes a day | 18 days |
| 30 minutes a day | 9 days |
| 45 minutes a day | 6 days |
| 60 minutes a day | 5 days |
Page count: median of 100 editions on Open Library. Times assume about 250 words per page. How we calculate.
#31 in Hercule Poirot
Next in the series: Elephants Can Remember (1972, 224 pages)
Your real reading speed
Time your sessions and Bookwisp learns how fast you actually read.
Start the timer when you open the book; it keeps running on your Lock Screen. Stop it, note your page, and your weekly minutes and streak update.
Hallowe'en Party: reading time questions
- How many pages is Hallowe'en Party?
- Hallowe'en Party is about 244 pages. That is the median across the 100 editions listed on Open Library; hardcover, paperback and large-print editions differ.
- How long does it take to read Hallowe'en Party?
- About 4 h 16 min at 238 words per minute, the average silent reading speed for adults. A quick reader at 300 words per minute needs about 3 h 23 min.
- How many days to read Hallowe'en Party at 30 minutes a day?
- About 9 days. At 15 minutes a day it takes about 18 days, and at an hour a day about 5 days.
- What number is Hallowe'en Party in the Hercule Poirot series?
- Hallowe'en Party is book 31 in Hercule Poirot by Agatha Christie.